Problem 1: Solution

 

 

      The net divergence in the layer from the LND to the tropopause was 1.00 X 10 –5 s -1.  The LND was at the 500 mb level an, on this day, the Tropopause was approximately located at the 200 mb level.  The tropopause was near the 200 mb level (11880 m)  and the LND is at the 500 mb level (5700 m)

 

Determine the vertical velocity at the LND in cm s-1.

 

                                  (1)

 

 

                            (2)

 

 

 

 

For the problem level 2 is 200 mb and level 1 is 500 mb.

 

 

 

 

and since the vertical velocity at 200 mb is zero.

 

 

z300 = 11880 m;  z500=5700 m

 

Hence

 

w500 = (1.00 X 10-5 s-1) (3970 m) = 6.2 cm s-1